Question: Is it possible to deserialize 'extra fields' to a dictionary object?

[Lazrius]

I am wondering if it is possible to collect all the extra fields within a Toml table, that were not processed into other fields/properties, into an Dictionary on the object. Something like this:

[TomlSerializedObject(NamingConvention = TomlNamingConvention.SnakeCase)]
public partial class Character
{
    [TomlValueOnSerialized] public required string Name { get; set; }
    [TomlValueOnSerialized] public required string Model { get; set; } 
    [TomlExtraFields] public required Dictionary<string, TomlValue> ExtraData { get; set; }
}

[[Character]]
name = "Test Character"
model = "models/characters/basic_skeleton.fbx"
cool_str = "A very cool string"
cool_number = 123 

In this example, it would example ExtraData would end up with two values, cool_str and cool_number. Is this or anything like this possible?

[prozolic]

Hello @Lazrius.
There is no feature to collect unmapped values into a separate field. Keys must correspond to properties marked with the [TomlValueOnSerialized] attribute.
As an alternative, you could implement manual handling using TomlDocument.